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Deep Impact
Deep Impact
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Deep Impact Mission Science Technology Mission Results Gallery Education Discovery Zone Your Community Press Discovery Zone - Mission Challenge

See National Math Standards for this Challenge.


In one way this is a bit of a trick question. Since both the comet and the impactor spacecraft will be moving in nearly the same orbit at the time of impact, what is important really is how fast the impactor spacecraft will be traveling relative to the comet. As an example of the importance of this difference, consider two cars involved in a rear-end collision. If both cars are moving at the time they collide, it isn't the velocity of the first car or the second car that would be used to calculate the energy of impact, it's the difference between them. So a car traveling at 60 mph striking a car traveling 55 mph transfers the same amount of energy at collision as a car traveling 5 mph striking a stationary car.

Another complication that has to be taken into account is the fact that the comet and impactor spacecraft will be moving through three-dimensional space, instead of the "one dimensional" space of the car example. Fortunately this can be fixed by thinking of the motion one piece at a time, using vectors.

3D Axes

If you assign the same x-y-z set of axes for both objects, their movement can be broken down into three components, an x-component, a y-component and a z-component. This gives you the velocity that the object is moving along that axis. The overall velocity of the object can be determined by simply adding up the vectors. Since the three vectors will be at right angles to each other (since they're along the three right-angle axes), we can just use the three dimensional form of the Pythagorean theorem:

Pythagorean Theorem (v squared equals x squared plus y squared plus z squared)

Vectors representing the velocity of two cars

Looking back at the car example, let's say that the cars were moving along the x-axis. This means that their velocities (in mph) along the three axes would be:
     Car 1: (60, 0, 0)
     Car 2: (55, 0, 0)

This means that the overall velocities of the cars would be:

Car 1: Equation for velocity of Car 1 = 60 mph

Car 2: Equation for velocity of Car 2 = 55 mph

Okay, enough hints. The last piece of information you need is the x, y, and z velocities (in kilometers per second) for the comet (27.09, -11.40, -5.46) and the impactor spacecraft (18.41, -12.67, -0.16). From these, can you determine the velocity of the impactor spacecraft relative to the comet at the time of impact?


Vectors representing overall velocity of the comet

Looking at the Deep Impact mission, the x, y, and z velocities (in kilometers per second) for the comet Tempel 1 at the time of impact are (27.09, -11.40, -5.46). This means the overall velocity of the comet is:

Equation for overall velocity of the comet

Vectors representing overall velocity of the impactor spacecraft

And the x, y, and z velocities (in kilometers per second) for the impactor spacecraft at the time of impact are (18.41, -12.67, -0.16). This means the overall velocity of the impactor spacecraft is:

Equation for overall velocity of the impactor spacecraft

At this point you may think; "Hey, wait a minute! Your mission description says the impactor spacecraft will be moving at 10.2 km/s. You messed up somewhere!" Think back to the car example from earlier. The relative velocity of the slower car to the other was only 5 mph, even though it was moving at 55 mph itself.

Now, you might be tempted at this point to say that the comet is just 7.5 km/s (29.9-22.4) faster than the impactor spacecraft, so the relative velocity of the impactor spacecraft will be 7.5 km/s. Unfortunately, this does not take into account the fact that the two objects will not be heading in exactly the same direction, like the cars were in the earlier example.

So, instead, to determine the relative velocity of the impactor spacecraft, you have to subtract each component (x, y, and z) of the comet from the impactor spacecraft, and then run the same type of 3D Pythagorean theorem calculation on the resulting relative components.

This works even in the "one dimensional" car example. The relative velocities of the second car will be: (55-60, 0-0, 0-0) or (-5, 0, 0). This means the overall relative velocity of the second car to the first is:

Equation for relative velocity of the second car to the first = 5 mph

Again looking at Deep Impact, the relative velocities of the impactor spacecraft then will be: (18.41-27.09, -12.67-(-11.40), -0.16-(-5.46)) or (-8.68, -1.27, 5.30). This means the overall relative velocity of the impactor spacecraft is:

Equation for relative velocity of the impactor spacecraft = 10.2 km/s

So, the impactor spacecraft will transfer the same amount of energy to the comet as it would if the comet were stationary and the impactor spacecraft were moving at 10.2 km/s.

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