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Deep Impact
Deep Impact
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Deep Impact Mission Science Technology Mission Results Gallery Education Discovery Zone Your Community Press Discovery Zone - Mission Challenge

See National Math Standards for this Challenge.


In more scientific terms, this question involves the maximum distance away from the target at which the target can be resolved.

Answering this question requires knowledge of the size of the target (comet Tempel 1 in this case), a nifty mathematical tool called the small angle formula, as well as how big a pixel is for the imager.

What is a pixel? Pixel is short for "picture element". The more pixels a picture is composed of, the more "real" it looks, and the more details you can make out - we'd say it is more resolved. As far as a computer analyzing data is concerned, a pixel is just a block of color. Put enough tiny blocks of color together in the right order, and to your eye you've got a nice picture.

If the comet is far enough away from the spacecraft, it fits inside one of the imager's pixels, and the comet is resolved as nothing more than a white dot. As the spacecraft gets closer, the comet overlaps more and more pixels, and more detail can be seen, or smaller details resolved.

The small angle formula is a mathematical formula used in astronomy for determining the angular diameter of an object that will appear as a disk when viewed from another object. It only works well for small angles - less than 10 degrees - thus its name. One way to present this formula is in this form:

a  =  diameter
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206265 arcseconds distance

Where "a" is the angular diameter of the object, in arcseconds*. The 206265 is a conversion factor that converts from radians to degrees, and then from degrees to arcseconds (it is equal to [360/2p] × 3600). "Diameter" is the object's true linear diameter, and "distance" is how far away the object is. These last two need to be in the same distance unit (both in meters, for example).

In the case of Deep Impact, we are told on the Instruments page for the High Resolution Instrument (HRI) that the size of a pixel will be 1.4 meters at a distance of 700 kilometers. The Medium Resolution Instrument (MRI) has a pixel size of 7 meters at a distance of 700 kilometers.

So, the questions you need to answer are...

  1. What is the angular diameter, in arcseconds, of a HRI pixel?
  2. What is the angular diameter, in arcseconds, of a MRI pixel?
  3. Given that the diameter of Tempel 1 is approximately 6 kilometers, how close (in kilometers) does the spacecraft have to be before the nucleus of the comet is bigger than 1 pixel on the HRI? How about for the MRI?
  4. How close will the comet have to be for its nucleus to cover 3 pixels (the minimum number to be considered more than random noise) on the HRI? How about the MRI?
  5. At the time of impact, the flyby spacecraft will be 234,641 km away from the comet (as we figured out in last month's Challenge). How many pixels across will the nucleus of the comet be on the HRI? How about the MRI?
  6. If the flyby spacecraft were not in shield mode at the time of its closest approach, when it's only around 508 km away from the comet (see last month's Challenge), how many pixels across would the nucleus of the comet be on the HRI? How about the MRI?
  7. The impactor spacecraft has a camera identical to the one in the flyby spacecraft's MRI. What is the closest the impactor spacecraft can be and still "see" the entire comet nucleus? The camera has an array that can effectively image 1008 x 1008 pixels.

*What is an arcsecond? An arc-second is one 60th (1/60) of an arcminute. An arcminute is one 60th (1/60) of a degree. Thus there are 3600 arc-seconds in one degree.

Idea from: Dennis Wellnitz & Elizabeth Warner

Click here for the answer...



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